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mov bh, al ; and bh, 01h ; This is pointless not bh and bh, 01h ;bh = !x2 You can take this farther: You're purely using bitwise operations and only care about the low bit in each register. You can and al, 1 once at the end to isolate the bit you want, with all the temporaries carrying around garbage in their high bits. WebOct 25, 2024 · Discuss. Basically, you are given a set of instructions and the initial content of the registers and flags of 8085 microprocessor. You have to find the content of the … marina e gabriel roncatti
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Web汇编语言OR指令:对两个操作数进行逻辑(按位)或操作 C语言中文网推出辅导班啦,包括 「C语言辅导班、C++辅导班、算法/数据结构辅导班」 ,全部都是一对一教学:一对一辅 … http://spike.scu.edu.au/%7Ebarry/interrupts.html WebOct 22, 2024 · ORG 100h .MODEL SMALL .DATA NUM_1 DB 0F2H NUM_2 DB 4H .CODE MOV BH, NUM_2 ;Load numerator in BH MOV AL, NUM_1 ;Load denominator in AL DIV BH … marina eiffe