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If the length of e.coli dna is 1.36 mm

WebIf the length of E. coli DNA is 1.36 mm, can you calculate the number of base pairs in E. coli ? 1,441 views Feb 8, 2024 24 Dislike Share Save Doubtnut 2.1M subscribers If the … WebQuestion: The genetic material of the Escherichia coli cell with a diameter of about 1 μm and a length of about 2 μm, consists of a DNA molecule with a diameter of 2 nm and a total length of 1.36 mm. (The molecule is actually circular, with a circumference of 1.36 mm.) To be accommodated in a cell that is only a few micrometers long, this large DNA molecule …

If the length of E.coli DNA is 1.36 mm ,what is the number of base …

Web14 nov. 2024 · july2013 Distance between two consecutive base pair = 0.34 nm Total length of given DNA = 1.36mm ∴ total no. of base pair = 1.36mm /0.34nm ⇒ 4 × 10⁶ Base pair. Advertisement abhi1o1 1.36 mm=0.36 cm lwgth of 10 base pair is 34angstrom so o.36*10^10/34=and and*9.8 or 10=ans is not it brilliant ans is there any doubt … Web27 mei 2024 · If the length of E.Coli DNA is 1.36 mm, Calculate the number of base pairs it contains. molecular basis of inheritance class-12 1 Answer +1 vote answered May 27, … the principal story documentary https://simul-fortes.com

Length of e.coli dna is 1.36mm ,calculate number of base pairs in e …

Web14 nov. 2024 · july2013 Distance between two consecutive base pair = 0.34 nm Total length of given DNA = 1.36mm ∴ total no. of base pair = 1.36mm /0.34nm ⇒ 4 × 10⁶ Base pair. … WebIf the length of E. coli DNA is 1.36 mm, can you calculate the number of base pairs in E. coli ? Class:12Subject: BIOLOGYChapter: MOLECULAR BASIS OF INHERITA... WebIf the length of E. coli DNA is 1.36 mm, can you calculate the number of base pairs in E.coli? In prokaryotes, such as, E. coli, though they do not have a defined nucleus, the DNA is not scattered throughout the cell. DNA (being negatively charged) is held with some proteins (that have positive charges) in a region termed as ‘nucleoid’. the principal square root of 0 is

If the length of E. coli DNA is 1.36 mm, then how many base …

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If the length of e.coli dna is 1.36 mm

If the length of E. coli DNA is 1.36 mm, can you calculate the

Web10 apr. 2024 · Sugarcane is a complex polyploid aneuploid cash crop, and transgenic varieties are important for molecular genetic and traditional breeding approaches. Herein, the sugarcane variety ROC22 served as the receptor, the Bar gene served as a screening marker, and positive and negative fragments of the ScD27.2 gene, upstream of … Web7 jul. 2024 · omegads04 Given, The total length of DNA= 1.36mm As we know, The distance between two consecutive base pairs is 0.34 * 10^-9 m Therefore, total length of double helix DNA of an organism can be calculated by multiplying the total number of base pairs with the distance between the two consecutive bp. Let the total number of bp be x

If the length of e.coli dna is 1.36 mm

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WebLength (total) of double helical DNA structure of E.coli=1.36 mm Note: 1.36mm =1.36 10−3 m Distance between the consecutive base pairs = 0.34 10−3m In the above equation, let … Web11 apr. 2024 · The domains A–D and CD were expressed in E. coli strain JCB7123 , while AB and full-length cytochrome were produced in E. coli strain BL21 (DE3) . ... The periplasmic fractions were dialyzed against 20 mM Tris-HCl buffer pH 8.5 (domain A), 10 mM Tris-HCl buffer pH 7.0 (domains C and D) ...

WebIf the length of E.coli DNA is 1.36 mm, calculate the number of base pairs it contains arrow_forward How many possible nucleotide sequences are there for a stretch of … Web19 feb. 2024 · Length of E coli DNA = 1.36 mm Hence the number of base pairs = 1.36 mm/34*10-6 mm The answer for this is 4*106 basepairs. Advertisement july2013 Distance between two consecutive base pair = 0.34 nm Total length of given DNA = 1.36mm ∴ total no. of base pair = 1.36mm /0.34nm ⇒ 4 × 10⁶ Base pair. Advertisement Advertisement

Web26 jan. 2024 · If the length of E. coli DNA is 1.36 mm, then how many base pairs are present in E. coil ? 8.01x - Lect 28 - Hydrostatics, Archimedes' Principle, Bernoulli's … Web8 apr. 2024 · Collateral sensitivity (CS), whereby resistance to one drug is accompanied by increased sensitivity to another, provides new opportunities for antimicrobial drug discovery. Here, Liu et al. screen ...

WebNo. of base pair Length between 2 bases Total length= 0.34×10−91.36×10−3= 4× 106.

WebIf the length of E.coli DNA is 1.36 mm, calculate the number of base pairs it contains Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution … the principal starch used in making sauceWebSolution: In the given case, the number of base pairs for E. coli would be 4×106 bp. It can be calculated as. Average distance between two base pairs of DNA is 3.4A˚. Length of E. coli DNA is = 1.36× 107A˚. So, number of nucleotides = 3.4A˚1.36×107A˚ = 0.39 ×107. sigma free fire pcWeb4 apr. 2024 · Since we are given the length of the DNA of E.coli as 1.36 mm, we can divide this value by the distance between two consecutive base pairs to get the total number of … sigma fresh air